Question

A horizontal froce of 490N is required to slide a block of 600kg weight.What is the coefficient of friction

Answer 1

600 kg wt = 600N normal force.
Kinetic force = 490N
∴ Co-efficient of friction = Fk/N = 490/600 = 0.8167

Answer 2

mass =600kg

force=490N

g=9.8

co efficient of friction=(mg)=490

co efficient of friction=490. 1

------ = --- = 0.083

9.8×600. 12