A horizontal froce of 490N is required to slide a block of 600kg weight.What is the coefficient of friction
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28
600 kg wt = 600N normal force.
Kinetic force = 490N
∴ Co-efficient of friction = Fk/N = 490/600 = 0.8167
Kinetic force = 490N
∴ Co-efficient of friction = Fk/N = 490/600 = 0.8167
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4
mass =600kg
force=490N
g=9.8
co efficient of friction=(mg)=490
co efficient of friction=490. 1
------ = --- = 0.083
9.8×600. 12
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