Question

A horizontal jet of water coming out of pipe of cross section area 20 cm square hits a vertical wall with velocity of 10m per second and rebounds with the same speed the force exerted by the water on the wall is

Answer 1

The change in velocity is 20 m/s.

ForceF=m(v-u)/t

m=vd=ALd; hereA is area.l is length of pipe.

F=ALd(v-u)/t,butL/t=v

F=Avd(v-u)plug in the values and get the answer

Answer 2

Answer:

Please check the pic here this is the answer