A horizontal jet of water is made to hit a vertical wall with a negligible rebound.If the speed of water from the jet is 'v'the diameter of the jet'd' and density is rho then the forceexcerted on the wall by the jet of water is
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We know that ,
Force exerted = Rate of change in linear momentum
= f = p/t = m•v/t = rho×v×l×A/t
= f = rho•A×v² [Since, l/t = v]
= f = rhoπ/4d²v² [ Since, A = π•d²/4]
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