Question

A horizontal moving rocket has velocity given by v=10-2t it's accleration is given by

Answer 1

Hey.

Velocity is given by , v = 10 - 2t

As acceleration is given by

$a = \frac{dv}{dt} \\ \\ so \: \: a \: = \frac{d(10 - 2t)}{dt} \\ \\ or \: \: a \: = - 2$


So, acceleration will be -2 or a retardation of 2 units .

Thanks.

Answer 2

Answer: a=-2 $m/s^{2}$

Explanation:

• Given v=10-2t and to find acceleration.
• We know we get acceleration when we differentiate velocity with respect to time i.e., $a=\frac{dv}{dt}$.

• $\frac{dv}{dt}=10-2t$

     ∴ a= -2  $m/s^{2}$

• Hence, the acceleration when v=10-2t is -2.

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