Question

A horizontal pipe has a diameter of 10.0 cm fluid flows in the pipe at 0.500 m/s The pipe is attached to a smaller pipe that has a diameter of 4.00 cm what is the speed of the fluid in the smaller pipe?
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Answer 1

Answer:

25cm/s

Step-by-step explanation:

Rate of flow, A * v, must remain constant. Use the continuity equation, A1v1=A2v2.

Solving the initial cross-sectional area yields: A1=πr2=25πcm2. The initial radius is 5cm.

Then find the final area of the pipe: A2=πr2=9πcm2. The final radius is 3cm.

Using these values in the continuity equation allows us to solve the final velocity.

(25πcm2)(9cm/s)=(9πcm2)v2

v2=25cm/s