A horizontal plank has a rectangular block placed on it the plank starts oscillating vertically and simple harmonically with an amplitude
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The plank starts oscillating vertically and simple harmonically with an amplitude of 40 cm.
What happens is that the block loses contact with the plank when the latter is at rest.
Then the period of the oscillation is zero when it is on the topmost position
The omega square = g omega that is equals to 40 cm when is later converted into m then we get the answer.
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