A horizontal rod AB carries three loads of 3.0 kg, 7.0 kg and 10.0 kg at distances of 2.0 cm, 9.0 cm and 15 cm respectively from A where it is hinged. Neglecting the weight of the rod, which is the point at which the rod will be balance ?
A. 10.45 cm form A B. 11.25 cm from A C. 12.55 cm from A D. 13.25 cm form A
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Thanks for asking the question.
Let us suppose the distance of the balancing point be ''y''cm from Z.
Balancing moments of loads,
(15-y) 10 = (x-9) 7 + (y-2) 3
150 - 10y = 10y - 6
20y = 219
y = 219/20
y = 10.45cm from Z
Hope it helps.
Let us suppose the distance of the balancing point be ''y''cm from Z.
Balancing moments of loads,
(15-y) 10 = (x-9) 7 + (y-2) 3
150 - 10y = 10y - 6
20y = 219
y = 219/20
y = 10.45cm from Z
Hope it helps.
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