Physics, asked by sreeraj1473, 1 month ago

A horizontal solid cylinder (of mass m) is pivoted about its longitudinal axis .To the end of thread wrapped on the cylinder a block (of mass 2m)is attached If the system is left free, acceleration of the block is (string is massless and there is no sliping anywhere)​

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Answered by himanshuchelani25
0

Explanation:

https://www.toppr.com/ask/question/mass-m-is-pivoted4-may-be-conserved-even-if-nelthe-system-is-nonzero28-a-horizontal

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Answered by shilpa85475
0

A solid horizontal cylinder (weight m) is thrown around the axis of length and the end of the rope is wrapped around the block (2m weight) attached If the system is left free, the speed of the block is:

  • The solid cylinder of the uniform weight M and radius R are shown in the center freely around the horizontal axis.
  • The non-stretchable wire is wrapped, and then connected to a mass m block that starts at h height above the floor.
  • Acceleration due to gravity by g, directed downwards.
  • At 2m,
  • Applying Newton's second law
  • 2 mg − T = 2 ma
  • For me,
  • As t = Ia
  • using a = rα, as there is no slip
  • TR=12mr2ar

     ⇒2T=ma    ∴2 mg−ma2=2 ma

     ⇒2g=a2+2a=5a2

        ∴  a=4g5=8 ms−2.

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