Math, asked by Himabindu2617, 1 year ago

A horse and 2 cows cost rs.480. if a horse costs 80 more than a cow, find the cost of each.

Answers

Answered by neosingh
3
Let cost of horse = h
cost of cow = c

ATq
h + 2c = 480 (1)
h - c = 80 (2)
Solve

(1) - (2)
2c +c = 400
c = ₹400/3
h = c + 80 = 400/3 + 80 =₹ 640/3

Answered by Anonymous
4
heya !!

here is ur answer

===========================

Given :-

➡ 1 horse , 2 cows cost 480.

➡ horse cost 80 more than cow .

--------------

let the cost of cow = X

ACQ

cost of horse = X + 80.

both together cost. 480

♦ X + X + 80 = 480

♦ 2x + 80 = 480

♦ 2x = 480 - 80

♦ 2x = 400

♦ X = 400/2

♦ X = 200

hence the cost of cow = 200

♦ cost of horse = X + 80

♦ 200 + 80

-------------------

cost of cow = 200

cost of horse = 280

---------------------

verification :-

200 + 280 = 480

==========================

hope it helps u..!!

♦ 280
Similar questions