A horse and 2 cows cost rs.480. if a horse costs 80 more than a cow, find the cost of each.
Answers
Answered by
3
Let cost of horse = h
cost of cow = c
ATq
h + 2c = 480 (1)
h - c = 80 (2)
Solve
(1) - (2)
2c +c = 400
c = ₹400/3
h = c + 80 = 400/3 + 80 =₹ 640/3
cost of cow = c
ATq
h + 2c = 480 (1)
h - c = 80 (2)
Solve
(1) - (2)
2c +c = 400
c = ₹400/3
h = c + 80 = 400/3 + 80 =₹ 640/3
Answered by
4
heya !!
here is ur answer
===========================
Given :-
➡ 1 horse , 2 cows cost 480.
➡ horse cost 80 more than cow .
--------------
let the cost of cow = X
ACQ
cost of horse = X + 80.
both together cost. 480
♦ X + X + 80 = 480
♦ 2x + 80 = 480
♦ 2x = 480 - 80
♦ 2x = 400
♦ X = 400/2
♦ X = 200
hence the cost of cow = 200
♦ cost of horse = X + 80
♦ 200 + 80
-------------------
cost of cow = 200
cost of horse = 280
---------------------
verification :-
200 + 280 = 480
==========================
hope it helps u..!!
♦ 280
here is ur answer
===========================
Given :-
➡ 1 horse , 2 cows cost 480.
➡ horse cost 80 more than cow .
--------------
let the cost of cow = X
ACQ
cost of horse = X + 80.
both together cost. 480
♦ X + X + 80 = 480
♦ 2x + 80 = 480
♦ 2x = 480 - 80
♦ 2x = 400
♦ X = 400/2
♦ X = 200
hence the cost of cow = 200
♦ cost of horse = X + 80
♦ 200 + 80
-------------------
cost of cow = 200
cost of horse = 280
---------------------
verification :-
200 + 280 = 480
==========================
hope it helps u..!!
♦ 280
Similar questions
Physics,
8 months ago
Computer Science,
8 months ago
English,
1 year ago
Chemistry,
1 year ago
Social Sciences,
1 year ago
Science,
1 year ago