Question

A horse and a cart together cost * 1600. If the cost of the cart was one-third of the cost of the horse, what did the horse cost?

please explain the ans
if you know then only​

Answer 1

Step-by-step explanation:

A person bought a horse and a carriage for Rs. 20,000. Later, he sold the horse at 20% profit and the carriage at 10% loss. Thus, he gained 2% in the whole transaction. The cost price of the horse was?

Let the cost of horse be Rs 100X

Cost of carriage = Rs ( 20,000 -100X )

Sale of horse = Rs 120X

Sale of carriage = Rs ( 0.9 (20,000 -100X ))= 18000- 90X

Total sale value = 120X + 18000–90X = 18000+30X

At 2% gain , total sale value has to be Rs 20,400

18000 +30X = 20,400

30X = 2400

X = 80

cost of horse = Rs 8000 ANSWER

Answer 2

⠀⠀❝Given that, A horse and a cart together cost 1600. & the cost of the cart was one-third of the cost of the horse. ❞

⠀

$\bullet \: \: \underline{ \pmb{ \frak{Need \: to \: find:} }} \: \sf{Cost \: of \: the \: horse?}$

⠀

A S S U M P T I O N S :

• Let the cost of cart be y & Let the cost of horse is x RS.

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━

⠀⠀⠀

✇ x + y = 1600 ..[Eq - 1]

✇ y = x × 1/3 i.e x/3 ..[Eq - 2]

⠀⠀⠀

$\bullet \: \: \underline{ \pmb{ \frak{Substituting \ the \ value \ of \ \sf{ y} \ in \ Equation \ 1} }}$

$\twoheadrightarrow \sf x + \dfrac{x}{3} = 1600 \\ \\ \\ \twoheadrightarrow \sf \dfrac{x + 3x}{3} = 1600\\ \\ \\ \twoheadrightarrow \sf \dfrac{4x}{3} = 1600\\ \\ \\ \twoheadrightarrow \sf x = \cancel{\dfrac{4800}{4} } \\ \\ \\ \twoheadrightarrow \sf \boxed{\pmb{ \mathfrak{x = 1200}}}$

⠀⠀⠀

Therefore,

• x = 1200
• y = x/3 i.e 1200/3 = 400.

⠀⠀⠀

$\therefore{\sf{\underline{ Thus, The \ cost \ of \ horse \: is \: \pmb{\bf{1200}} \: \& \: cost \: of \: cart \: is \: \pmb{\bf{400}.}}}}$