Question

A Horse and a cart together cost rupees 1600.If cost of the cart was one third of the cost of the horse what did the horse cost??????????.

Answer 1

ANSWER

Two horse selling price =11,900

let the 1st S.P =x

Second horse S.P =(11,900−x)

Given that

1st horse C.P= Second of S.P

and then⇒

70

x×100

=(11,900−x)

10x=(11,900−x)×7

10x=83300−7x

10x+7x=83300

17x=83300

x=4900

1st horse C.P =

70

4900×100

=7000

Second horse C.P =

125

(11900−4900)

×100

125

7000×100

=5600

Total C.P =7000+5600

=12600

And than

lose=12600−11900

=700Rs

Answer 2

Answer:

Horse+Cart= 1600 Rs.

Cost of the Cart= 1/3 ( Let the cost of the cart be x )

Cost of the Horse= ? ( Let the cost of the horse be y)

First, we are going to convert the cost of the cart in rupees.

x+y=1600

x/3=y

x+x/3=1600

4x/3=1600

4x=4800

x=1200

Now, we are going to find out the price of the horse.

x/3=y

1200/3=y

y=400

Hope it helps you.