Question

A horse and two cows together cost 680. If a horse cost 80 more than a cow, find the cost of each.

Answer 1

Answer:

horse =280 , cow =200

Step-by-step explanation:

let

cost of horse = x

cost of cow=y

given cost of horse is 80 more than cow

so cost of horse = y+ 80

according to given statement

y+80+2×y=680

y+80+2y=680

3y+80=680

3y=680- 80

3y=600

y =600÷3 = 200

so cost of cow =y=200

cost of horse = y + 80=200+80=280

Answer 2

Step-by-step explanation:

let horse be x and cow be y

given x=80+y

and also x+2y=680 eq 1

so 80+y+2y=680

80+3y=680

3y=680-80

y=200

sub in eq 1

we get

x=280