Question

A horse and two cows together cost 680. If a
horse cost 80 more than a cow, find the cost of
each.​

Answer 1

The horse costs $280 and two cows cost $400 or $200 a peice

Answer 2

Answer:

Step-by-step explanation: Let the price of a cow be x

[(x+80) + 2x] = 680

[x+2x] = 680-80 = 600

3x=600

x= 600/3= 200

Price of one cow= 200 rupees

Price of a horse= 200+80= 280

Pls mark me brainliest and follow me if this helped you