Question

A horse drinks water from a cubical container of side 1 m. The level of the stomach of horse is at 2 m from the ground. Assume that all the water drunk by the horse is at a level of 2m from the ground. Then minimum work done by the horse in drinking the entire water of the container is (Take $\rho_{water}$ = 1000 kg/m³ and g = 10 m/s²) –(a) 10 kJ(b) 15 kJ(c) 20 kJ(d) zero

Answer 1

may be c)20kj....!!

Answer 2

w= f*d

= mgh

= 1000*10*2 wkt

= 20kJ m= v *ρ

= a∧3 *ρ

= 1000kg