a horse exerts a pull on a cart of 300N. this makes the horse cart move with a uniform speed of 18 km/h on a level road calculate the power developed by horce in watt
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W =p×t
W= f×s
So p×t=f×s
Ans s i.e distance = speed ×tym
So 300×18×1 =p×1so
P=300×18 kwh
1 kwh = 3.6×10^6 joules
300×18×3.6×10^6joules
1944×10^7
W= f×s
So p×t=f×s
Ans s i.e distance = speed ×tym
So 300×18×1 =p×1so
P=300×18 kwh
1 kwh = 3.6×10^6 joules
300×18×3.6×10^6joules
1944×10^7
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