Question

a horse is placed for grazing inside a rectangular feild 70 m by 52 m and is tethered to one corner by a rope 21 m long. how much area can it graze ? ​

Answer 1

Answer:

AREA THAT HORSE CAN GRAZE = 346.5 SQUARE CM.

Step-by-step explanation:

$area \: of \: rectangle = 70 \times 52 \\ \\ = 3640 \: {m}^{2} \\ \\ area \: the \: horse \: can \: graze = \frac{\pi}{4} \times {21}^{2} \\ \\ = \frac{22}{7} \times \frac{1}{4} \times 21 \times 21 \\ \\ = \frac{11}{2} \times 3 \times 21 \\ \\ = \frac{11}{2} \times 63 \\ \\ = 346.5 \: {m}^{2} .$

Answer 2

Answer:

AREA THAT HORSE CAN GRAZE = 346.5 SQUARE CM.

Step-by-step explanation:

\begin{gathered}area \: of \: rectangle = 70 \times 52 \\ \\ = 3640 \: {m}^{2} \\ \\ area \: the \: horse \: can \: graze = \frac{\pi}{4} \times {21}^{2} \\ \\ = \frac{22}{7} \times \frac{1}{4} \times 21 \times 21 \\ \\ = \frac{11}{2} \times 3 \times 21 \\ \\ = \frac{11}{2} \times 63 \\ \\ = 346.5 \: {m}^{2} .\end{gathered}areaofrectangle=70×52=3640m2areathehorsecangraze=4π×212=722×41×21×21=211×3×21=211×63=346.5m2.