A horse is placed for grazing inside a rectangular field 70m by 52m and is teetered to one corner by rope 21st long. How much area can it graze
Answers
Answered by
314
Solution:-
Let EAF be a sector in the rectangular field ABCD.
The horse can graze in the sector EAF.
Length of the rope = 21 m = Radius of the sector EAF
∠ A = 90° (Angle of the rectangular field)
∴ Area of the sector EAF = 90/360 × πr²
= 90/360*22/7*21*21
= 873180/2520
= 346.5 sq m
Answer.
Let EAF be a sector in the rectangular field ABCD.
The horse can graze in the sector EAF.
Length of the rope = 21 m = Radius of the sector EAF
∠ A = 90° (Angle of the rectangular field)
∴ Area of the sector EAF = 90/360 × πr²
= 90/360*22/7*21*21
= 873180/2520
= 346.5 sq m
Answer.
Answered by
111
Area that the horse can graze.
=x/360×πr2
=90/360 ×22/4(21) (21)
= 33×21/2=693/2=346.5squ.m
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