a horse is placed for grazing inside a square field 12m long and is tethered to one corner by a rope with a length which is two third of the length of the field.the approximate area horse can graze is:
a. 48m^2 b.50m^2 c.51m^2 d.54m^2
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length of the rope is 2/3 of the length of field
so length of the field = (12) - (12 * 2/3)m = 4m
area in which horse can graze = πr^2
= 3.14 * 4m * 4m = 50.24 m^2
approximate area in which horse can graze = 50m^2
kthat0047:
if u don't mind could you elaborate the second step?
yes
value of π is 3.14 and the length of the rope is 4m
the area in which the horse can graze is π*r*r
and I had taken approx of 50.24 that is 50
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this is the answer
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