Question

A horse is tied to a pole at the corner of a square field of side 12 m by a rope of length 3.5 M.
find the area of the part of the field in which the horse can graze

Answer 1

1/4th of circular region of radius 3.5 M as Horse can only graze between two adjacent edges of square ... So. area grazed = 1/4πr^2 = 1/4*22/7*3.5*3.5 = 9.625 M^2

Answer 2

Area of part that horse can graze
= area of quadrant
=
$\frac{90}{360} \times \frac{22}{7} \times 3.5 \times 3.5$
$\frac{1}{4} \times 22 \times .5 \times 3.5$
$\frac{1}{4} \times 38.5$
= 9.625
Hence, horse can graze 9.625 sq. m of area.
Hope it help.