A horse of mass of 60kg moving with initial velocity 45m/s after some time the is finalvelc velocity becomes 60m/s find the work done by the horse
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Given:-
→ Mass of the horse = 60kg
→ Initial velocity of the horse = 45m/s
→ Final velocity of the horse = 60m/s
To find:-
→ Work done by the horse
Solution:-
We know that:-
Work done = Change in K.E.
=> K.E. = 1/2mv²
Thus:-
=> W = 1/2mv² - 1/2mu²
=> W = m/2[ v² - u² ]
=> W = 60/2[ (60)² - (45)² ]
=> W = 30[ 3600 - 2025 ]
=> W = 30×1575
=> W = 47250 J
=> W = 47.25 kJ
Thus, work done by horse is 47.25 kJ .
Some Extra Information:-
• Work done by a force on a body is the product of force and displacement of a body.
=> W = F × s
• Work is a scalar quantity.
• S.I. unit of work is joule (J).
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