Question

A horse pulls a trolley with a force 100N at an angle of 60degree from horizontal how much work done by the horse in a min if he moves with speed of 18 Km per hours

Answer 1

speed = 18km/hr.
=18 × 5/18 mt/sec
=5 mt/sec

time = 1 min.
=60 sec.

distance = speed × time
s = 5 × 60 = 300 mt.

work done = Fscos60°
=100 × 300 × 1/2
=15000m
=15 km

Answer 2

$\maltese \: \red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

It is given that :-

• Force applied by horse = 100N
• Horizontal angle = 60°
• Time = 1min = 60s.
• Speed of horse = 18km/h = 18 × 5/18 = 5m/s

Now, the speed of horse is 5m/s. And the time for which it moves is 1min (60s).

Thus, the distance Traveled by horse will be = speed × time

= 5 × 60 = 300m.

Now the force applied by horse with a horizontal angle 60 ° is 100N.

Thus the work done by horse will be :

$\maltese \: w = f \times s \times cos\theta$

$\maltese \: w = 100 \times 300 \times \frac{1}{2}$

$w = 50 \times 300 = 15000J = 15kJ$

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BY SCIVIBHANSHU

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