Question

a hose ejects water at speed of 20cmpersecond through a hole of area100cmsquare.if the water srikes a wall normally calculate the force on the wall in newton assuming the velocity of the water normal to the wall is zero after collison.

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Answer 1

Answer:

mass of water ejects per second = Area*velocity = 1000cm3/s = 10-3m3/s

so force = change in momentum = m*v = 10-3*10-1 = 10-4N