Question

A hose pipe lying on the ground shoots a stream of water upward at an angle 60 degree to the horizontal at a speed of 20 meter / second the water strikes a wall 29 meters away at a height ( G=10 / seconds square

Answer 1

Answer:

The water strikes a wall 29 meters away at a height 8.18 m

Explanation:

The trajectory of water will be that of a projectile

The angle of projection θ = 60°

Initial velocity u = 20 m/s

Resolving the velocity into two components

The horizontal component of the velocity

$u_x=20\cos60^\circ=20\times\frac{1}{2} = 10 \text{ m/s}$

And the vertical component of the velocity

$u_y=20\sin60^\circ=20\times\frac{\sqrt{3} }{2} = 10\sqrt{3} \text{ m/s}$

The horizontal distance covered by the stream = 29 m

There is no acceleration in the horizontal direction

Therefore, using distance = speed x time

$29=u_x\times t\\\implies 29=10\times t\\\\\implies t=2.9 \text{ sec}$

Now we need to find the vertical displacement in time 2.9 seconds

using the second equation of motion

$h=u_y\times t-\frac{1}{2} gt^2$

$h=10\sqrt{3} \times 2.9-\frac{1}{2} \times 10\times 2.9^2$

$\implies h=8.18 \text{ m}$