A hospital has 16 isolation rooms.each room has a patient with a different illness .patient in room 13 recovers and wants to say goodbye to each patients. he can only visit each patient once. if he visit a patient twice he becomes ill again. how does he do this and exit from room 4?
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It is said that no patient is allowed to see him more than once. But room no. 13 is his own so he can visit his cell twice or more times if required.
However three possible ways arise.
- See the first picture. 13 > 14 > 13 > 9 > 10 > 11 > 15 > 16 > 12 > 8 > 7 > 6 > 5 > 1 > 2 > 3 > 4
- See the second picture. 13 > 9 > 13 > 14 > 10 > 11 > 15 > 16 > 12 > 8 > 7 > 6 > 5 > 1 > 2 > 3 > 4
- See the third picture. 13 > 9 > 13 > 14 > 10 > 6 > 5 > 1 > 2 > 3 > 7 > 11 > 15 > 16 > 12 > 8 > 4
Read more on Brainly:
- A prisoner who died in cell number 13, How to take his body out of the prison through Gate 4. the conditions : The body must pass through all the cells for all prisoners to see. No prisoner (bold for a reason ) is allowed to see him more than once. - https://brainly.in/question/16517949
- The person in roon no.13 and wants to go out through 4. He wants to meet his person in each room before going out. Conditon is he cannot enterthe other rooms twice. - https://brainly.in/question/16538581
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Room 13 - 14 - 13 - 9 - 10 - 11 - 15 - 16 - 12 - 8 - 7 - 6 - 5 - 1 - 2 - 3 - 4 - out
Step-by-step explanation:
The patient in room 13 will take the route shown in the picture. He will visit Room 14 and return to his own room, then visit Room 9, 10, 11, 15, 16, 12 in that order. After this it is pretty simple, he will just pass through the rest of the rooms in order until he exits out of Room 4.
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