Math, asked by shashikumar3744, 9 months ago

A hospital has 16 isolation rooms.each room has a patient with a different illness .patient in room 13 recovers and wants to say goodbye to each patients. he can only visit each patient once. if he visit a patient twice he becomes ill again. how does he do this and exit from room 4?​

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Answered by MajorLazer017
13

➢ Question (nice question) :

A hospital has 16 isolation rooms.each room has a patient with a different illness .patient in room 13 recovers and wants to say goodbye to each patients. he can only visit each patient once. if he visit a patient twice he becomes ill again. how does he do this and exit from room 4?

➢ Answer :

We are given,

⇝ Person in the room 13 can only visit other rooms only once.

⇝ At the same time, he also has to get out through room 4 (after visiting all other patients).

_______________________________

∴ The only way he can get out (by following the given conditions) would be to follow the pattern given below :

13 – 9 – 13 – 14 – 15 – 16 – 12 – 11 – 10 – 6 – 5 – 1 – 2 – 3 – 7 – 8 – 4 – Out.

Hence, the recovered patient is now able to meet all other patients (once) and at the same time get out through room no. 4 (without becoming ill again).

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