Math, asked by Reetikakiro, 2 months ago

A hostel needs 68 kg 980 g of provision in 1 day. How much provision is required for 15 days?

Answers

Answered by swarnalatasamal

2

Answer:

in 1 day provision requirement=68 kg 980 gm

so for 15 days=15×68 kg 980 GM

=1034.7 kg

Answered by mehuladhana

0

Answer:

2425 kg 700 g Ans

Step-by-step explanation:

68 multiply by 15 : 1020

980 multiply by 15 : 14,700

14 + 1020 : 2425

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