Question

a hot air balloon m,is 900 metres vertically above a point n on the ground.a boy stands at a point o,1200 metres horizontally from n.calculate the distance om,of the boy from the saloon.

Answer 1

here,

In triangle MNO,

By Pythagoras' Theorem,

${om}^{2} = {mn}^{2} + {on}^{2}$

Now, substituting the values, we get,

${om}^{2} = {900}^{2} + {1200}^{2}$

${om}^{2} = 810000 + 1440000$

${om }^{2} = 2250000$

$om = \sqrt{2250000}$

om=1500m

Therefore, the distance of the boy from the balloon is 1500m.