Question

A hot iron ball of mass 2.5kg is dropped into 0.5kg of water at 10°C. The final temperature

recorded is 30°C. Calculate the temperature of hot iron ball. Specific heat capacity of iron=
8 cal/gm°C , Specific heat capacity of water=4.2J/gm°C.

​

Answer 1

Answer:

so the answer will we 3kg 40c

Answer 2

Answer:

If heat losses to the surroundings are not negligible, is your answer greater or smaller ... 150cm3 of water at 27oC. The final temperature is 40oC. Compute the ... Mass (M) of water at temperature T = 27oC:

Mass of the metal, m = 0.20 kg = 200 g

Initial temperature of the metal, T

1

= 150

o

C

Final temperature of the metal, T

2

= 40

o

C

Calorimeter has water equivalent of mass, m = 0.025 kg = 25 g

Volume of water, V = 150 cm

3

Mass (M) of water at temperature T = 27

o

C:

150×1=150g

Fall in the temperature of the metal:

ΔT

m

=T

1

-T

2

=150−40=110

o

C

Specific heat of water, C

w

=4.186J/g/K

Specific heat of the metal =C

Heat lost by the metal, =mCT .... (i)

Rise in the temperature of the water and calorimeter system: T

1

−T=40−27=13

o

C