Physics, asked by rani3744, 1 year ago

A hot liquid contained in a container of negligible heat capacity loses temperature at rate 3K/min,just before it begins to solidify.The temperature remains constant for 30min . Find ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 (given that rate of losing heat is constant)

Answers

Answered by rohityadav1829
10
The temperature remains constant for 30min . Find ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 (given that rate of losing heat is  
Answered by Anonymous
12

Answer:

1:90

Explanation:

Temperature loss = 3K/min (Given)

Constant temperature = 30 mins (Given)

Let the mass be = m

Let the specific heat capacity be = c

Let the latent heat of fusion be = L

Let the heat change = Q

Using the equation -

Q = 3 × 30

Q = 90k

Q = mct  = 90 and t is the temperature change,

Thus, t = 90/mc K

L = Q/m

or L = ( 90/mc)/m

or L/c = 90K

or c/L = 1/90 K^-1

Thus the ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 is 1:90.

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