A hot liquid contained in a container of negligible heat capacity loses temperature at rate 3K/min,just before it begins to solidify.The temperature remains constant for 30min . Find ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 (given that rate of losing heat is constant)
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The temperature remains constant for 30min . Find ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 (given that rate of losing heat is
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Answer:
1:90
Explanation:
Temperature loss = 3K/min (Given)
Constant temperature = 30 mins (Given)
Let the mass be = m
Let the specific heat capacity be = c
Let the latent heat of fusion be = L
Let the heat change = Q
Using the equation -
Q = 3 × 30
Q = 90k
Q = mct = 90 and t is the temperature change,
Thus, t = 90/mc K
L = Q/m
or L = ( 90/mc)/m
or L/c = 90K
or c/L = 1/90 K^-1
Thus the ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 is 1:90.
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