Question

A hot liquid contained in a container of negligible heat capacity loses temperature at rate of 3k/min,just before it begin ro solidify the temperature remains constant for 30min find the ratio of specific heat capacity of liquid to specfic latent heat of fussion is in k

Answer 1

mhflufouflufpufpufoydoydy

Answer 2

Answer:

Explanation:

Loss of temperature = 3K/min (Given)

Constant temperature = 30 mins (Given)

Let the mass be = m

Let the latent heat of fusion be = L

Let the heat change = Q

Substituting the values in the equation -  

Q = 3 × 30

Q = 90k

Q = mct  = 90 and t is the temperature change, ( where c is the specific heat)

Thus, t = 90/mc K

L = Q/m

or L = ( 90/mc)/m

or L/c = 90K

or c/L = 1/90 K^-1  

Thus the ratio of specific heat capacity of liquid to specific latent heat of fusion in K^-1 is 1:90.