Question

A hot solid of mass 60 g at 100°C is placed in 100 g of water at 18°C. The final temperature

recorded is 20°C. Find the heat capacity of the solid​

Answer 1

Answer:

0.175g

Explanation:

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Answer 2

Answer:

A hot solid of mass 60 g at 100°C is placed in 100 g of water at 18°C. The final temperature  recorded is 20°C. The heat capacity of the solid​ will be $0.175\ \mathrm{Jg}^{-1} \mathrm{K}^{-1}$

Explanation:

• Let M be the mass of water, m be the mass of the solid, T be the temperature of the water, t be the temperature of the solid and, θ be the final temperature.

• We can solve this problem using the principle of calorie meter.

       According to the principle of calorie meter,

       Heat gained by water =Heat lost by the solid

       That is,

       $\mathrm{MC}_{1}(\mathrm{~T}-\theta)=m \mathrm{C}_{2}(\theta-t)$

       Where

       $C_1$ - Specific heat capacity of water

       $C_2$ - Specific heat capacity of solid

In the question, it is given that,

$M = 100 g$          $m=60 \mathrm{~g}$    

$T = 18^0C$           $t = 100^0C$    

$\theta = 20^0C$            $C_1 = \text { 4.2 Joule } \mathrm{g}^{-1} \mathrm{~K}^{-1}$

Substitute these values into the above equation,

$100 \times 4.2(18-20)=60 \times \mathrm{C}_{\mathrm{2}} \times(20-100)$

$C_{2}=\frac{(-840) }{(-80 \times 60)} =0.175\ \mathrm{Jg}^{-1} \mathrm{K}^{-1}$