Question

A hot solid of mass 60g at 100°C is placed in 150g of water at 20°C. The final steady temperature recorded is 25°C. Calculate the specific heat capacity of the solid.(Specific heat capacity of water = 4200Jkg-¹C-¹)​

Answer 1

Answer:

Heat gained = Heat lost

150×4.4×(25−50)=60×c×(100−25)

150×4.2×5=60×c×75

Specific heat capacity (c)=0.7Jg

−1

o

C

−1

hope it will helps u...

Answer 2

Answer:

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Explanation:

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