Question

A hot water system(Geyser)consists of a cylindrical pipe of length 14 m and diameter 5 cm. find the total radiating surface of hot water system.WITH PROCESS

Answer 1

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Answer 2

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✴.Radius[R] = $\frac{diameter}{2} ={5}{2}$ =2.5Cm.

Length of the pipe = height =14m

Radiating surface = 2${\phi}$ rh

2${\phi}$ $\frac{22}{7}$ × 2.5 × 1400

=22000${cm}^3$

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