Math, asked by premvidyarthibha, 1 year ago

A hotel had 80 guests. Two-fifth of them were women and the rest were nen. How many men were staying in the hotel?

Answers

Answered by yajmera8
39

total guests in hotel = 80

Women guests = 2/5 of total

= 2/5×80

32 guests are women

So rest of them are men= 80-32=48 guests

Answered by AmritanshuKeshri56
16

Solution:- A hotel had 80 guests. Two-fifth of them were women and the rest were men.

No. of Women = 2/5 ×80 = 32

No. of Women + No. of men = 80

=> 32 + x = 80

=> x = 80 - 32

=> x = 48

[Therefore, No. of men = 48]


Anonymous: Good :)
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