Question

A hound runs after a rabbit. The rabbit is 87.5 meters ahead of the dog. By the time the rabbit jumps 4, the dog jumps 3, if the dog and the rabbit go
$2 + \frac{3}{4}$
meters and
$1 + \frac{1 }{4}$
meters respectively in one jump, how many jumps will the dog catch the rabbit. ​

Answer 1

Answer:

the dog would overtake rabbit in 526 leaps.

Explanation:

Answer is 526 leaps.

Rabit is 125*1.75=218.75 meters ahead of dog.

In one time frame dog takes 3 leaps and rabbit takes 4 leaps.

In one time frame, dog goes ahead of rabbit by 3*2.75 - 4*1.75 = 1.25 meters.

in order to cover distance of 218.75 meters, dog would require 218.75 / 1.25= 175 time frames.

In 175 time frames dog would take 175*3 = 525 leaps.

So, after 525 leaps, the dog would catch the rabbit.

therefore, the dog would overtake rabbit in 525+1 = 526 leaps.

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