Math, asked by harrypotterofficiala, 7 months ago

A house costs 36% more today than when it was build. If the cost of the house today is $333200, find its cost when it was built


please solve this.

Answers

Answered by harshithasinghthakur
1

Step-by-step explanation:

Let the cost of house, when it was built be x.

Today its cost= x+x*(36/100) ...(1)

But its cost today is $333200 [given] ...(2)

Now, equating (1) and (2),

We get,

x+x*(36/100)=333200

x+(36x/100)=333200

(100x+36x)/100=33200 [taking LCM of denominator]

136x/100=333200

136x=333200*100 [rearranging terms]

x=33320000/136

Therefore,

x= $245,000.

Thus, the cost of the house when it was built was $245,000

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Hope it helped (◕ᴗ◕✿)

Answered by Anonymous
0

Answer:

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