A house has 1 bulb of 40W, one fan of 60W 1 refrigerator of 250W. They are used 8 hours per day. What is the cost of energy for 30 days at Rs. 8 per kWh?
Answers
Answered by
2
Answer:
The answer to this question is = Rs 672
Explanation:
Total power used in one day =
(40 + 60 + 250) * 8
= 350 * 8
= 2800 W h
= 2.8 KWh
The power used in 30 days = 2.8 * 30
= 84 KWh
Therefore The cost = 84 * 8 = Rs 672
I HOPE IT WILL HELP YOU.
If you like it please mark it as Brainliest Answer
Answered by
1
Answer:
power=40+60+250=350watt
=350/1000 kilowatts
or 0.35 kilowatts
time in hours=30×8=240
power=energy consumed/time taken
-》0.35 =energy consumed/240 h
energy consumed=0.35×240=84 kilowatts
cost of energy at rate of 8 rupees per KWH
=84×8=672 rupees
please mark as BRAINLIEST
Similar questions