Question

A house has 10 cylindrical pillars each having radius 50cm and height 3.5 cm. Find the curved surface area of the pillars ​

Answer 1

curved surface area of cylinder = 2πrh

=>2π*50*3.5

=>2*²²/7*50*³⁵/10

=>2*22*50*½

=>2*22*25

=>44*25

=>1100

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Answer 2

Answer:

$\bigstar{\bold{CSA\:of\:ten\:pillars=11000\:cm^{2}}}$

Step-by-step explanation:

$\Large{\underline{\rm{Given:}}}$

• Number of pillars = 10
• Radius of cylinders = 50 cm
• Height = 3.5 cm

$\Large{\underline{\rm{To\:Find:}}}$

• Curved surfaace area of the pillars

$\Large{\underline{\rm{Solution:}}}$

⇝ Given that the pillars are cylindrical in shape.

⇝ First we have to find the curved surface area of one pillar.

⇝ CSA of a pillar is given by,

    CSA of a cylinder = 2 π r h

    where r is the radius

    h is the height

⇝ Substituting the data,

    CSA of a pillar = 2 × 22/7 × 50 × 3.5

    CSA of a pillar = 2 × 22 × 50 × 0.5

    CSA of a pillar = 1100 cm²

⇝ Hence the curved surface area of a pillar is 1100 cm².

⇝ Now curved surface area of 10 pillars is given by,

    CSA of 10 pillars = 10 × CSA of one pillar

⇝ Substitute the data,

    CSA of 10 pillars = 10 × 1100

    CSA of 10 pillars = 11000 cm²

⇝ Hence the curved surface area of 10 pillars is 11100 cm².

    $\boxed{\bold{CSA\:of\:ten\:pillars=11000\:cm^{2}}}$

$\Large{\underline{\rm{Notes:}}}$

⇝ CSA of a cylinder = 2 π r h

⇝ TSA of a cylinder = π r (r + h)

⇝ Volume of a cylinder = π r² h