Question

A house has 3 tube-lights of 20 watts each. On the average, all the tube-lights are
kept on for five hours. Find the energy consumed in 30 days.​

Answer 1

Answer:

Commercial unit of energy is kwh

Sir unit of energy is joule

Explanation:

P=20 watt=20/1000kwh

T=5hrs

No of days -30 days

Therefore. E=20/1000* 5*30

=6kwh (6 units)

Answer 2

Answer:

The energy consumed is $9$ $kWh$.

Explanation:

Given that :

Number of tube lights $= 3$

Wattage of the tube lights $= 20$ watts each

Number of consumed hours $=5$ hours

Therefore,

Energy $= \frac{3 * 20 * 5}{1000}$

$= \frac{300}{1000}$ $kWh$

$= 0.3 kWh$

So, the consumed energy for 30 days $= 0.3 *30$ days

 $= 9 kWh$ or, $9$ units.

kWh : A kilowatt hour (kWh) is a unit of measurement for the amount of energy consumed each hour.

The kilowatt-hour is commonly abbreviated as "kWh," which is derived from its two constituent units, kilowatt and hour.

It's a billing term used by electric utility companies to describe how much energy they've given to their customers.