a house hold uses 2 electric fans each of rating 80W for 8 hrs a day and 4 electric tubes each of rating 20W for 10hrs a day. calculate the amount of electrical energy consumed in the month of june
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Answer:
Energy consumed = power×time
Energy consumed by 2 electric fans = 2×80×8 = 1280W/hr
Energy consumed by 4 electric tubed = 4×20×10 = 800W/hr
Total energy consumed in a day = 1280+800 = 2080W/hr = 2.08KWh
Energy consumed in a month of June = 30×2.08 = 62.4KWh.
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