Math, asked by tanmoy20144, 1 year ago

A house is advertised at a price which is actually 25% more than the cost price.if the hous6e owner reduces the price by 10% of the advertised price, what will his gain or loss percent

Answers

Answered by enyo
39

Answer: Owner's gain percent would be 12.5%.


Step-by-step explanation:

Let x be the cost price of a house.

Since advertised price is 25% more than the cost price, so

advertised price= 125% of x= 1.25x

But when the owner reduces the price by 10% of the advertised price, we see that

The new advertised price= 90% of 1.25x= 0.90*1.25x= 1.125x

Because the advertised price is more than the actual cost price, there would be a gain.

gain= new advertised price - actual cost price

= 1.125x - x= 0.125x

gain percent= gain/cost price*100= 0.125x/x*100= 12.5%

Therefore, his gain percent would be 12.5%.

Answered by rajakpreeti473
11

12.5%

Step-by-step explanation:

this is the answer

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