Question

a house is consuming two bulbs of 100w-5hr/day and a fan of 70w- 20 hours per day. Calculate the electrical energy consumed in a month (30days​

Answer 1

Answer:

$\sf\underline{ \rm {72kwh}}$

Explanation:

Given:

Power of bulb= 2×100=200W

Time = 5 hours

energy consumed by 2 bulbs=200×5

$= 1000 \sf{ \rm {W/ \: day}} \\ = \frac{1000}{1000 } = 1kw/h \: \sf{per \: day}$

$\sf{and \: energy \: consumed \: by \: fan = \frac{70w \times 20hr}{1000} }$

$= \sf{1.4kw/h/day}$

$\therefore \: \sf{total \: energy \: consumed \: bt \: 2bulbs + 1fan}$

$= \sf{1 + 1.4 = 2.4kwh/ \: per \: day}$

$\therefore \sf{total \: energy \: consumed \: in \: a \: month(30days)}$

$= \sf{2.4 \times 30 = 72kwh.}$

Answer 2

Answer:

$\sf \huge \underline{refers \: in \: attachment}$