Question

A house is fitted with 20 bulbs rated 100 W each, 10 fans each running at 0.5A and an electric kettle of 100 ohm resistance. Electricity is supplied at 220 V & at a rate of Rs 2 per unit. Calculate the energy consumption per month if all the appliances are used for 6 hrs a day.

Answer 1

Dear Mridul,

◆ Answer -

Energy consumption per month = 516 units

Electricity bill per month = ₹ 1032

● Explanation -

Energy consumed by bulbs is -

Eb = n × P × t

Eb = 20 × 100 × 6×24

Eb = 288000 Wh

Eb = 288 kWh

Energy consumed by fans is -

Ef = n × V × I × t

Ef = 10 × 220 × 0.5 × 6×24

Ef = 158400 Wh

Ef = 158.4 kWh

Energy consumed by electric kettle is -

Ek = V² × t / R

Ek = 220² × 6×24 / 100

Ek = 69696 Wh

Ek = 69.696 kWh

Total energy consumption is calculated by -

E = Eb + Ef + Ek

E = 288 + 158.4 + 69.7

E = 516.1 kWh/month

Total electricity bill per month will be -

Bill = E × cost

Bill = 516 × 2

Bill = ₹ 1032 /month

Therefore, electricity bill will be ₹ 1032 per month.

Answer 2

Explanation:

mark me as a brainliest