Question

. A house is sold for 96,00,000. If the profit made by the owner is 20%, find the cost price of the house.

Answer 1

Given :-

SP = ₹96,00,000

Profit percentage = 20%

To Find :-

The Cost Price of the house

1st Method :-

Let the CP be ₹x

Profit = 20% of x

$=\: {\dfrac{20 \times x}{100}}$

$=\: {\dfrac{x}{5}}$

SP = CP + Profit

$=\: x\: +\: {\dfrac{x}{5}}$

$=\: {\dfrac{5x + x}{5}}$

$=\: {\dfrac{6x}{5}}$

But, Also given that SP = ₹96,00,000

A/q,

${\dfrac{6x}{5}}\: = 96,00,000$

$=>\: 6x\: =\: 96,00,000 \times 5$

$=>\: x\: =\: {\dfrac{96,00,000 \times 5}{6}}$

=> CP = ₹8000000

Therefore, The cost price of the house is ₹80,00,000

2nd Method (By Formula) :-

$CP\: =\: {\dfrac{SP \times 100}{100 + Profit\: percentage}}$

On inserting the values in the formula

We get ,

$CP\: =\: {\dfrac{9600000 \times 100}{100 + 20}}$

$CP\: =\: {\dfrac{9600000 \times 100}{120}}$

=> CP = 8000000

Therefore, The cost price of the house is ₹80,00,000

Answer 2

Answer:

$\huge \bold {question}$

A house is sold for 96,00,000. If the profit made by the owner is 20%, find the cost price of the house

$\huge \bf \: to \: find$

Cost price of the house .

$\huge \bf \: solution \:$

$\: cp \: = \: \frac{sp \: \times 100}{100 + profit \: percent}$

$cp \: = \frac{9600000 \times 100}{100 + 20}$

$cp \: = 8000000$

✴️Extra keywords✴️

C.P = Cost price

S.P = Selling price