A household refrigerator absorbs heat at 2⁰ C and rejects heat to the surroundings at 50⁰ C. Its compressor is driven by 3 kW motor and 50 MJ/hr are absorbed at the low temperature. The irreversibly in J/hr is given as:
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Question From class 11 Chapter THERMODYNAMICS
In a refrigerator one removes heat from a lower temperature and deposits to the surroundings at a higher temperature. In this process, mechanical work has to be done, which is provided by an electric motor. If the motor is of 1kW power and heat transferred from
C to
C, find the heat taken out of the refrigerator per second assuming its efficiency is 50% of a perfect engine.
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Text Solution
Solution :
Given, temperature of the source is
C <br>
<br> Temperature of sink
<br> Efficiency of a perfect heat engine is given by <br>
<br> Efficiency of refrigerator is 50% of a perfect engine <br>
<br>
Coeffcient of performance of the refrigerator <br>
<br>
<br>
<br> Therefore, heat is taken out of the refrigerator at a rate of 19 kJ per second.
Explanation:
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Answer:
11. A household refrigerator absorbs heat at 2°C and rejects heat to the surrounding at 50°C. Its compressor is driven by 3kW motor and 50 MI/hr are absorbed at the low temperature. Evaluate the amount of heat rejected per hour and irreversibility in /hr. (60800kJ/hr.
Explanation:
11. A household refrigerator absorbs heat at 2°C and rejects heat to the surrounding at 50°C. Its compressor is driven by 3kW motor and 50 MI/hr are absorbed at the low temperature. Evaluate the amount of heat rejected per hour and irreversibility in /hr. (60800kJ/hr.