Physics, asked by Anonymous, 19 days ago

A household refrigerator that has a power input of 450 W and a COP of 2.5 is to cool five large watermelons, 10 kg each, to 8°C. If the watermelons are initially at 20°C, determine how long it will take for the refrigerator to cool them. The watermelons-can be treated as water whose specific heat is 4.2 kJ/kg-°C.

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Answered by obabar598
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Answer:

A household refrigerator that has a power input of 450 W and a COP of 2.5 is to cool five large watermelons, 10 kg each, to 8°C. If the watermelons are initially at 20°C, determine how long it will take for the refrigerator to cool them. The watermelons-can be treated as water whose specific heat is 4.2 kJ/kg-°C.

Explanation:

A household refrigerator that has a power input of 450 W and a COP of 2.5 is to cool five large watermelons, 10 kg each, to 8°C. If the watermelons are initially at 20°C, determine how long it will take for the refrigerator to cool them. The watermelons-can be treated as water whose specific heat is 4.2 kJ/kg-°C.

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