Question

A household uses the following electric appliance:
(i) Refrigerator of rating 400Wfor ten hours each day.
(ii) Two electric fans of rating 80W each for twelve hours each day.
(iii) Six electric tubes of rating 18W each for six hours each day.
Calculate the electricity bill of the household for the month of June if the cost per unit
of electric energy is 3.00 ​

Answer 1

1kwh=1unit , for one day...unit for referiigerater=400×10/1000, unit(refre.)=4 , unit for twoelectric fans=80×2×12/1000, unit(ele.fan)=1.92 , unit for six electric tubes=18×6×6/1000, unit(elect.tubes)=0.648 and in June month 30days present so for one day all house hold appliances 4+1.92+0.648=6.568 then for June month 30×6.568=197.04 and for one unit cost is 3.00 so 197.04×3=591.12 cost