A household uses the following electric appliances : 1) Refrigerator of rating 400W for 10 hours each day 2) 3 electric fans of rating 80W each for 12 hours each day 3) 5 electric tubes of rating 18W each for 6 hours each day Calculate the electricity bill of the household for the month of June, if the cost per unit of electric energy is Rs.3
Answers
Question
A household uses refrigerator has a rating of 400W for 10hrs each day, 2 electric fans of rating 80W each for 12hrs each day, 6 electric bulbs rating 18W each for 6hrs. Calculate the electricity bill for month of June if the cost per unit is ₹3.
Answer
Given, power of refrigerator = 400W, power of each electric fans = 80W, power of each electric bulbs = 18W
Time taken to use this electrical appliances by:
- Refrigerator used = 10hrs each day,
- Electric fans used = 12hrs each day,
- Electric bulb used = 6hrs each day
Power of refrigerator = 400W, Power of 2 electric fans = 2 × 80W = 160W, Power of 6 electric bulbs = 6 × 18W = 108W
Now, the total power of all these electrical appliances = 400W + 160W + 108W = 668W
& the total time taken duration of consumption by these electrical appliances for a month of June is = 10hrs + 12hrs + 6hrs = 28hrs × 30 = 840hrs.
Therefore, Total energy consumed will be = 668W × 840hrs
= 0.668KW( Kilowatt ) × 840hrs
= 0.67 × 840hrs
= 67/100 × 840 = 2814/5 = 562.8KWh( Kilowatt hour )
Hence, The total cost per unit in the month of June = 562.8 × ₹3 = ₹1688.4
★ Ans : ₹1688.4 ★
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