Question

a household uses the following electric appliances

a)refrigerator of rating 400w for 10 hours each day.
b)two electric fan of rating 80w each for 6 hours each day.c)six electric tubes of rating 18w each for 6 hours each day.calculate the electricity bill of household for the month of june if the cost per unit of electric energy is Rs.3

Answer 1

a) Power = 400 W =0.4 KW hr

Time = 10 hr

Energy consumed by refrigerator in one day  = P x T

= 0.4 x 10

= 4 KW hr

b) total power consumed  by 2 fans = 2 x 80 W = 160 W = 0.16 KW

Time  = 6 hr

Energy consumed by 2 fans in one day = P x T

= 0.16 x 6

= 0.96 KW hr

c) total power consumed by 6 tube lights = 6 x 18 W = 108 W = 0.108 KW

Time = 6 hr

Energy consumed in one day = P x T

= 0.108 x 6

= 0.648 KW hr

Total Energy consumed in one day = 4 + 0.96 + 0.648

= 5.608 KW hr

Total energy used in month of June = 30 x 5.608 [ june = 30 days ]

= 168.24 KW hr

Cost  of energy used in month of June = 3 x 168.24

= Rupees 504.72

Answer 2

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