a household uses the following electric appliances
a)refrigerator of rating 400w for 10 hours each day.
b)two electric fan of rating 80w each for 6 hours each day.c)six electric tubes of rating 18w each for 6 hours each day.calculate the electricity bill of household for the month of june if the cost per unit of electric energy is Rs.3
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24
a) Power = 400 W =0.4 KW hr
Time = 10 hr
Energy consumed by refrigerator in one day = P x T
= 0.4 x 10
= 4 KW hr
b) total power consumed by 2 fans = 2 x 80 W = 160 W = 0.16 KW
Time = 6 hr
Energy consumed by 2 fans in one day = P x T
= 0.16 x 6
= 0.96 KW hr
c) total power consumed by 6 tube lights = 6 x 18 W = 108 W = 0.108 KW
Time = 6 hr
Energy consumed in one day = P x T
= 0.108 x 6
= 0.648 KW hr
Total Energy consumed in one day = 4 + 0.96 + 0.648
= 5.608 KW hr
Total energy used in month of June = 30 x 5.608 [ june = 30 days ]
= 168.24 KW hr
Cost of energy used in month of June = 3 x 168.24
= Rupees 504.72
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