Question

A household uses the following electric appliances :(i) Refrigerator of rating 400W for ten hours each day.

(ii) Two electric fans of rating 80W each for twelve hours each day.

(iii) Six electric tubes of rating 18W each for 6 hours each day.

Calculate the electricity bill of the household for the month of June if the cost

per unit of electric energy is Rs. 3.00.​

Answer 1

Answer:

Energy consumed by refrigerator of rating 400 W for ten hours each day,

ii) Energy consumed by two electric fans of rating 80 W each for twelve hours each day is,

iii) Energy consumed by six electric tubes of rating 18 W each for 6 hours each day is,

Total energy consumed in the month of June (30 days) is given by,

= (0.8 + 1.92 + 0.648) x 30 kWh

= 6.568 x 30

= 197.04 kWh

Electricity bill for the month of June = Rs 197.04 x 3

= Rs 591.12

= Rs 591 (approx.)